Я пытаюсь вернуть успешную функцию dropzone, но она не работает. Мне нужно вернуть путь и имя изображения на страницу загрузки изображений ...
Мой код:
<body>
<button id="submit-all">Submit all files</button>
<form action="uploads.php" class="dropzone" id="my-dropzone"></form>
<script>
Dropzone.options.myDropzone = {
// Prevents Dropzone from uploading dropped files immediately
addRemoveLinks: true,
autoProcessQueue: false,
maxFilesize:100,
parallelUploads:5,
maxFiles:5,
acceptedFiles: "image/*,.pdf, application/vnd.openxmlformats-officedocument.spreadsheetml.sheet, application/vnd.openxmlformats-officedocument.spreadsheetml.template, application/vnd.openxmlformats-officedocument.presentationml.template, application/vnd.openxmlformats-officedocument.presentationml.slideshow, application/vnd.openxmlformats-officedocument.presentationml.presentation, application/vnd.openxmlformats-officedocument.presentationml.slide, application/vnd.openxmlformats-officedocument.wordprocessingml.document, application/vnd.openxmlformats-officedocument.wordprocessingml.template, application/vnd.ms-excel.addin.macroEnabled.12, application/vnd.ms-excel.sheet.binary.macroEnabled.12,text/rtf,text/plain,audio/*,video/*,.csv,.doc,.xls,.ppt,application/vnd.ms-powerpoint,.pptx",
init: function() {
var submitButton = document.querySelector("#submit-all"),
myDropzone = this; // closure
submitButton.addEventListener("click", function() {
myDropzone.processQueue(); // Tell Dropzone to process all queued files
});
}
};
</script>
</body>
И загрузите скрипт:
$upload_dir = 'uploads';
if (!empty($_FILES)) {
$tempFile = $_FILES['file']['tmp_name'];
echo $tempFile;
// using DIRECTORY_SEPARATOR constant is a good practice, it makes your code portable.
$targetPath = dirname( __FILE__ ) . DIRECTORY_SEPARATOR . $upload_dir . DIRECTORY_SEPARATOR;
// Adding timestamp with image's name so that files with same name can be uploaded easily.
$mainFile = $targetPath.time().'-'. $_FILES['file']['name'];
move_uploaded_file($tempFile,$mainFile);
} else { echo 'error: no file'; }
Мне нужна функция успеха, чтобы вернуть путь к загруженным изображениям. Спасибо.
